题目描述

The cows have opened a new business, and Farmer John wants to see how well they are doing. The business has been running for N (1 <= N <= 100,000) days, and every day i the cows recorded their net profit P_i (-1,000 <= P_i <= 1,000).

Farmer John wants to find the largest total profit that the cows have made during any consecutive time period. (Note that a consecutive time period can range in length from one day through N days.) Help him by writing a program to calculate the largest sum of consecutive profits.

牛们开了家新公司，这家公司已经运作了N天，财务报表显示第i天获得的利润为Pi ， 有些天的利润可能是个负数。约翰想给奶牛公司写个新闻报道，以吹嘘她们的业绩。于是他 想知道，这家公司在哪一段连续的日子里，利润总和是最大的。

输入输出格式

输入格式：

• Line 1: A single integer: N

• Lines 2..N+1: Line i+1 contains a single integer: P_i

输出格式：

• Line 1: A single integer representing the value of the maximum sum of profits for any consecutive time period.

输入输出样例

输入样例#1：

7 -3 4 9 -2 -5 8 -3

输出样例#1：

14

说明

The maximum sum is obtained by taking the sum from the second through the sixth number (4, 9, -2, -5, 8) => 14.

簡單動規。（因為方程沒法應付全負的情況，加了個l特判）

代碼實現：

1 #include
     
       2 #include
      
        3 using namespace std; 4 int n,a,b,c,l=-3000,f[2][2]; 5 int main(){ 6     scanf("%d",&n); 7     for(int i=1;i<=n;i++){ 8         scanf("%d",&a); 9         b=i%2;c=(b+1)%2;l=max(l,a);10         f[b][0]=max(f[c][0],f[c][1]);11         f[b][1]=max(f[c][1]+a,a);12     }13     if(l>=0) printf("%d\n",max(f[n%2][0],f[n%2][1]));14     else printf("%d\n",l);15     return 0;16 }
      
     

還記得嗎？